0=n^2+n-992

Solution for 0=n^2+n-992 equation:

0=n^2+n-992

We move all terms to the left:

0-(n^2+n-992)=0

We add all the numbers together, and all the variables

-(n^2+n-992)=0

We get rid of parentheses

-n^2-n+992=0

We add all the numbers together, and all the variables

-1n^2-1n+992=0

a = -1; b = -1; c = +992;
Δ = b2-4ac
Δ = -12-4·(-1)·992
Δ = 3969
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3969}=63$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-63}{2*-1}=\frac{-62}{-2}
=+31
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+63}{2*-1}=\frac{64}{-2}
=-32
$